C语言实现树的动态查找实例代码

2025-05-27 0 81

C语言实现动态查找实例代码

本例演示一种数据结构存储记录集合时的动态查找方法。首先程序通过construct()函数,利用已经存在的结构体数组数据建立一个二叉,建立的过程中,要保证每个节点的值都大于它的左子上节点的值而小于它右子所有节点的值,该函数返回建立的根指针;然后通过函数Search(root,name)查找,如果找到相应的数据,将其打印出来,如果没有找到,则用户可以选择是否将该数据插入到中。

具体代码如下:

?

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17

18

19

20

21

22

23

24

25

26

27

28

29

30

31

32

33

34

35

36

37

38

39

40

41

42

43

44

45

46

47

48

49

50

51

52

53

54

55

56

57

58

59

60

61

62

63

64

65

66

67

68

69

70

71

72

73

74

75

76

77

78

79

80

81

82

83

84

85

86

87

88

89

90

91

92

93

94

95

96

97

98

99

100

101

102

103

104

105

106

107

108

109

110

111

112

113

114

115

116

117

118

119

120

121

122

123

124

125

126

127

128

129

130

131

132

133

134

135

136

137

138

139

140

141

142

143

144

145

146

147

148

149

150

151

152

153

154

155

156

157

158

159

160
#include <stdio.h>

#include <stdlib.h>

#include <string.h>

#define NUM 4

struct tree

{

char name[20];

char city[20];

char sex[10];

char age[10];

char job[10];

struct tree *left;

struct tree *right;

};

struct tree Datas[NUM]=

{

"Willing","Tianjing","Female","21","worker",NULL,NULL,

"Tom","Beijing","Male","31","doctor",NULL,NULL,

"Sun","Weifang","Male","24","student",NULL,NULL,

"Marry","Shanghai","Female","19","techer",NULL,NULL

};

struct tree *construct(

struct tree *root,

struct tree *r,

struct tree *Data)

{

if(!r)

{

r = (struct tree *)malloc(sizeof(struct tree));

if(!r)

{

printf("内存分配失败!");

exit(0);

}

r->left = NULL;

r->right = NULL;

strcpy(r->name,Data->name);

strcpy(r->city,Data->city);

strcpy(r->sex,Data->sex);

strcpy(r->age,Data->age);

strcpy(r->job,Data->job);

if(!root)

return r;

if(strcmp(Data->name,root->name)<0)

root->left = r;

else

root->right = r;

return r;

}

if(strcmp(Data->name,r->name)<0)

construct(r,r->left,Data);

else

construct(r,r->right,Data);

return root;

}

struct tree *Search(root,name)

struct tree *root;

char name[];

{

struct tree *p;

if(root == NULL)

printf("该树为空\\n");

p = root;

while(strcmp(p->name,name)!=0)

{

if(strcmp(p->name,name)>0)

p = p->left;

else

p = p->right;

if(p == NULL)

break;

}

return(p);

}

void print(struct tree *r)

{

if(!r)

return;

print(r->left);

printf("%s\\n",r->name);

print(r->right);

}

void print_currentData(struct tree *point)

{

if(point == NULL)

return;

printf(" 姓名:%s\\n",point->name);

printf(" 城市:%s\\n",point->city);

printf(" 性别:%s\\n",point->sex);

printf(" 年龄:%s\\n",point->age);

printf(" 工作:%s\\n",point->job);

}

int main(void)

{

int i;

char c[10];

char swap[20];

char name[20];

struct tree *root,*p;

struct tree *temp;

p = NULL;

temp = NULL;

root = NULL;

for(i = 0;i<NUM;i++)

root =construct(root,root,&Datas[i]);

printf("现有人员资料:\\n");

print(root);

printf("请输入要查找的人的名字\\n");

scanf("%s",name);

p = Search(root,name);

if(p == NULL)

{

printf("没有该人资料\\n");

printf("是否要插入该人资料[y/n]\\n");

scanf("%s",c);

if(strcmp(c,"y")==0)

{

temp = (struct tree *)malloc(sizeof(struct tree));

if(!temp)

{

printf("内存分配失败!");

exit(0);

}

printf("请输入该人姓名:\\n");

scanf("%s",swap);

strcpy(temp->name,swap);

printf("请输入该人所在城市:\\n");

scanf("%s",swap);

strcpy(temp->city,swap);

printf("请输入该人性别[Male/Female]:\\n");

scanf("%s",swap);

strcpy(temp->sex,swap);

printf("请输入该人年龄:\\n");

scanf("%s",swap);

strcpy(temp->age,swap);

printf("请输入该人工作:\\n");

scanf("%s",swap);

strcpy(temp->job,swap);

temp->left = NULL;

temp->right = NULL;

root =construct(root,root,temp);

print_currentData(temp);

printf("现有人员资料:\\n");

root = root;

print(root);

}

else

return 0;

}

print_currentData(p);

return 1;

}

感谢阅读,希望能帮助到大家,谢谢大家对本站的支持!

收藏 (0) 打赏

感谢您的支持,我会继续努力的!

打开微信/支付宝扫一扫,即可进行扫码打赏哦,分享从这里开始,精彩与您同在
点赞 (0)

声明:本站所有文章,如无特殊说明或标注,均为本站原创发布。任何个人或组织,在未征得本站同意时,禁止复制、盗用、采集、发布本站内容到任何网站、书籍等各类媒体平台。如若本站内容侵犯了原著者的合法权益,可联系我们进行处理。

快网idc优惠网 建站教程 C语言实现树的动态查找实例代码 https://www.kuaiidc.com/74000.html

相关文章

发表评论
暂无评论