C语言实现俄罗斯方块小游戏

2025-05-27 0 27

C语言实现俄罗斯方块小游戏的制作代码,具体内容如下

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#include <stdio.h>

#include <stdlib.h>

#include <unistd.h>

#define TTY_PATH "/dev/tty"

#define STTY_ON "stty raw -echo -F"

#define STTY_OFF "stty -raw echo -F"

int map[21][14];

char direct;

int node[7][4][16]={

{{0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},//长方形

{0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0},

{0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},

{0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0}},

{{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},//正方形

{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},

{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},

{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0}},

{{0,1,0,0,1,1,1,0,0,0,0,0,0,0,0,0},//3边加一中点

{0,1,0,0,0,1,1,0,0,1,0,0,0,0,0,0},

{0,0,0,0,1,1,1,0,0,1,0,0,0,0,0,0},

{0,1,0,0,1,1,0,0,0,1,0,0,0,0,0,0}},

{{0,1,1,0,0,1,0,0,0,1,0,0,0,0,0,0},//右锄头型

{0,0,0,0,1,1,1,0,0,0,1,0,0,0,0,0},

{0,1,0,0,0,1,0,0,1,1,0,0,0,0,0,0},

{1,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0}},

{{1,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0},//左锄头型

{0,0,1,0,1,1,1,0,0,0,0,0,0,0,0,0},

{0,1,0,0,0,1,0,0,0,1,1,0,0,0,0,0},

{0,0,0,0,1,1,1,0,1,0,0,0,0,0,0,0}},

{{0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},//右曲折型

{0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0},

{0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},

{0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0}},

{{0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},//左曲折型

{1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0},

{0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},

{1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0}}

};

typedef struct block

{

int x;

int y;

int blockType;

int blockDirect;

}Block;

Block bl;

void init_map()//初始化边框

{

int i,j;

for(i=0; i<21; i++)

for(j=0; j<14; j++)

{

if(j==0 || j==13)

map[i][j] = 200;

else if(i==20)

map[i][j] = 201;

else

map[i][j] = 0;

}

}

void new_block()//生成随机的俄罗斯方块

{

int blockType = rand()%7;

int blockDirect = rand()%4;

int x = 1;

int y = 5;

bl.x = x;

bl.y = y;

bl.blockType = blockType;

bl.blockDirect = blockDirect;

}

void input()//将移动后的俄罗斯方块,导入地图中作标记

{

int i, j;

for(i=0; i<4; i++)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j]==1)

{

map[bl.x+i][bl.y+j] = 1;

}

}

void output()//移动时,将之前俄罗斯方块在地图信息清空。

{

int i, j;

for(i=0; i<4; i++)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j]==1)

{

map[bl.x+i][bl.y+j] = 0;

}

}

void change()//俄罗斯方格在碰撞后融入,固定

{

int i, j;

for(i=0; i<4; i++)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j]==1)

{

map[bl.x+i][bl.y+j] = 10;

}

for(j=1; j<13; j++)

if(map[5][j] == 10)

{

system("clear");

printf("game over !!!!!!!!!\\n");

exit(1);

}

}

void print_map()//打印地图,显示信息

{

int i,j;

for(i=5; i<21; i++)

{

for(j=0; j<14; j++)

{

if(map[i][j]==200)//左右边界

printf("#");

else if(map[i][j]==201)//下边界

printf(" # ");

else if(map[i][j]==0)//空白地

printf(" ");

else if(map[i][j]==1)//移动的俄罗斯方块

printf(" * ");

else if(map[i][j]==10)//固定的俄罗斯方块

printf(" @ ");

}

printf("\\n");

}

}

void delLine(int n)//消行

{

int i,j;

for(j = 1; j<13; j++)

map[n][j] = 0;

for(i = n; i>5 ; i--)

for(j = 1; j<13; j++)

if(map[i-1][j] != 1)

map[i][j] = map[i-1][j];

}

void isFillLine()//是否满足消行条件

{

int i,j;

int fals;

for(i=19; i>5; i--)

{

fals = 1;

for(j=1; j<13; j++)

{

if(map[i][j] != 10)

{

fals = 0;

continue;

}

}

if(fals)

{

delLine(i);

}

}

}

void down()//下移

{

int i, j;

int fale = 1;

for(i=3; i>=0; i--)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)

if(map[bl.x+i+1][bl.y+j] == 10 || map[bl.x+i+1][bl.y+j] == 201)

{

change();

fale = 0;

new_block();

isFillLine();

return;

}

if(fale)

{

output();

bl.x += 1;

input();

}

}

void right()//右移

{

int i, j;

int fale = 1;

for(i=3; i>=0; i--)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)

if(map[bl.x+i][bl.y+j+1] == 10 || map[bl.x+i][bl.y+j+1] == 200)

{

fale = 0;

return;

}

if(fale)

{

output();

bl.y += 1;

input();

}

}

void left()//左移

{

int i, j;

int fale = 1;

for(i=3; i>=0; i--)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)

if(map[bl.x+i][bl.y+j-1] == 10 || map[bl.x+i][bl.y+j-1] == 200)

{

fale = 0;

return;

}

if(fale)

{

output();

bl.y -= 1;

input();

}

}

void change_block()//俄罗斯方块变形

{

int i,j;

output();

int fals = 1;

bl.blockDirect += 1;

bl.blockDirect %= 4;

for(i=0; i<4; i++)

for(j=0; j<4; j++)

if(node[bl.blockType][bl.blockDirect][i*4+j]==1)

if(map[bl.x+i][bl.y+j] != 0 )

{

fals = 0;

break;

}

if(fals)

{

input();

}else

{

bl.blockDirect -= 1;

input();

}

}

char in_direct()//非堵塞输入

{

fd_set fd;

struct timeval tv;

char ch;

FD_ZERO(&fd);

FD_SET(0, &fd);

tv.tv_sec = 0;

tv.tv_usec = 10;

if(select(1, &fd ,NULL, NULL, &tv) > 0)

{

ch = getchar();

}

return ch;

}

int main()//q 退出游戏,a,d 左右移动,空格变形

{

srand(time(NULL));

init_map();

new_block();

input();

char ch;

int num = 0;

while(1)

{

usleep(500000);

system(STTY_ON TTY_PATH);

ch = in_direct();

system(STTY_OFF TTY_PATH);

system("clear");

if(ch == 'a' && num <= 1)

{

left();

print_map();

num++;

continue;

}else if(ch == 'd' && num <= 1)

{

right();

print_map();

num++;

continue;

}else if(ch == ' ' && num <= 1 )

{

change_block();

print_map();

num++;

continue;

}else if(ch == 'q')

{

system("clear");

printf("gave over!!!!!\\n");

exit(0);

}

down();

print_map();

num = 0;

}

return 0;

}

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